Question

Amar deposited Rs 2000 in a bank at the rate of 5% p.a. Draw a linear graph between time and simple interest for 4 years. ​

Answer 1

To find

the simple interest for 4 year

solution -

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years implies

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4Put t = 4 in eq(1)

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4Put t = 4 in eq(1)I= 2000 x 4

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4Put t = 4 in eq(1)I= 2000 x 41 = 8000

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4Put t = 4 in eq(1)I= 2000 x 41 = 8000=> 8000Rs the simple interest for 4

S. I. (px rx t)/100 = = (20000 x 10 x t)/ 100S.I = 2000 t (1)simple interest of per 4 years impliest = 4Put t = 4 in eq(1)I= 2000 x 41 = 8000=> 8000Rs the simple interest for 4years

Answer 2

Answer:

Amar deposit rupees 2000 in a bank at the rate of 5% P.A draw a liner graph between time and simple interest for 4 years