Question

amar gives ₹9000 to some athletes of a school as scholarship every month had there been 20 more athletes each would have got ₹160 less.form a pair of linear equations for this

Answer 1

Money amar gives= 9000
let the number of athletes be in yhe beginning- X
assume each of them gets a scholarship Y
then according to the ques, XY=9000 (eq. #1)
in the second case the number of athletes is increased by 20 and the money is decreased by Rs160.
therefore,
(X+20) (Y+160) = 9000 (eq. #2)

Answer 2

Money amar gives is 9000
No of athletes is = x
Amount each gets as scholarship = y
Therefore the linear equation is = x×y=9000

Now in next case.
Money that amar gives remains constant.
But no of athletes increased by 20
Therefore No of athletes becomes = x+20
Now Amount each gets as scholarship =y-160
Because before the arrival of extra 20 members the amount each got as scholarship was y now after the arrival of the extra twenty members Each's scholarship got reduced by 160 Therefore amount each get as scholarship becomes y-160
Now the equation for this case becomes (x+20)(y-160)=9000
Hope you understood.