Math, asked by kushalbond108, 11 months ago

Amar is two years older than akbar, and akbar is twice the age of anthony.if their average age is 9, how old is akbar?

Answers

Answered by botanyliker
2

Answer:

let the Anthony 's age be x

then Akbar's age =2x

Anthony's age =2x+2

A to Q

average age =9

sum of ages =9×3

=2x+2+2x+x=27

=5x+2=27

=5x=27-2

=5x=25

=x=25/5

=x=5

Akbar's age =2x=2×5=10 years

Answered by Gautamsanswal
2

Step-by-step explanation:

let the age of anthony be x

then,

the age of Akbar is 2x

the age of Amar is 2x+2

avg age = sum of their ages/no of ages

avg age= x + 2x + 2x + 2(y)/3

if something divided by 3 is equal to 9 then y/3=9

y=9*3

y=27

sum if their ages=27

according to the statement:

x+2x+2x+2=27

5x+2=27

5x=27-2

5x=25

x=25/5

x=5

age of akbar=2x

age of akbar=2*5

=10

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