Math, asked by kushalbond108, 1 year ago

Amar is two years older than akbar, and akbar is twice the age of anthony.if their average age is 9, how old is akbar?

Answers

Answered by botanyliker
2

Answer:

let the Anthony 's age be x

then Akbar's age =2x

Anthony's age =2x+2

A to Q

average age =9

sum of ages =9×3

=2x+2+2x+x=27

=5x+2=27

=5x=27-2

=5x=25

=x=25/5

=x=5

Akbar's age =2x=2×5=10 years

Answered by Gautamsanswal
2

Step-by-step explanation:

let the age of anthony be x

then,

the age of Akbar is 2x

the age of Amar is 2x+2

avg age = sum of their ages/no of ages

avg age= x + 2x + 2x + 2(y)/3

if something divided by 3 is equal to 9 then y/3=9

y=9*3

y=27

sum if their ages=27

according to the statement:

x+2x+2x+2=27

5x+2=27

5x=27-2

5x=25

x=25/5

x=5

age of akbar=2x

age of akbar=2*5

=10

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