Amar rupees 9000 to som athletes of a school as a scholarship every month had there been 20 More athletes each would have got rupees 160 less from pole for this
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Money amar gives is 9000
No of athletes is = x
Amount each gets as scholarship = y
Therefore the linear equation is = x×y=9000
Now in next case.
Money that amar gives remains constant.
But no of athletes increased by 20
Therefore No of athletes becomes = x+20
Now Amount each gets as scholarship =y-160
Because before the arrival of extra 20 members the amount each got as scholarship was y now after the arrival of the extra twenty members Each's scholarship got reduced by 160
Therefore amount each get as scholarship becomes y-160
Now the equation for this case becomes (x+20)(y-160)=9000
Hope you understood.
No of athletes is = x
Amount each gets as scholarship = y
Therefore the linear equation is = x×y=9000
Now in next case.
Money that amar gives remains constant.
But no of athletes increased by 20
Therefore No of athletes becomes = x+20
Now Amount each gets as scholarship =y-160
Because before the arrival of extra 20 members the amount each got as scholarship was y now after the arrival of the extra twenty members Each's scholarship got reduced by 160
Therefore amount each get as scholarship becomes y-160
Now the equation for this case becomes (x+20)(y-160)=9000
Hope you understood.
honeysingh96:
Aise baita apne ghar walo se bola kr apni maa behan se aur jyada aag lagi ha to aja ek min m thanda kr dunga wahi se bhonk skta tu suar
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