Question

Amars age is three times his son's age. Ten
years
ago he was five time his son's
age find there present ages​

Answer 1

Answer:

Amars son is 20 yrs old

Amar is 3x=3×20=60 yrs old.

Step-by-step explanation:

Let Amar's son age =x

Amar's age =3x

Ten years ago, he was 5 times the age of his son.

Therefore, 3x−10=5(x−10)

3x−10=5x−50

2x=40

x=20

Amar's son is 20 yrs old

Amar is 3x=3×20=60 yrs old.

Answer 2

Answer :-.

• Amar's age = 60 years.
• His son's age = 20 years.

Given :-

• Amar's age is three times his son's age.
• Ten years ago, he was five times his son's age.

To find :-

• Their present ages.

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Step-by-step explanation :-

Let Amar's son's age be x.

Since Amar's age is three times his son's age, therefore his age = 3x.

Ten years ago, Amar's age = 3x - 10.

Then his son's age = x - 10.

As given in the question,

Ten years ago, Amar was 5 times his son's age.

So, Amar's age was 5 × x - 10 (His son's age).

Therefore, we get :-

$\sf \bf3x - 10 = 5 \: (x - 10)$

$\sf \bf3x - 10 = 5x - 50$

$\sf \bf3x - 5x = - 50 + 10$

$\sf \bf- 2x = - 40$

$\sf \bf x = \dfrac{ - 40}{ - \:2}$

$\sf \bf x = 20.$

Since the present age of Amar's son is 20 years,

Therefore Amar's age = 3 × 20 = 60 years.

So,

Amar's age = 60 years.

His son's age = 20 years.

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