Question

Amay jumps 5.25m,5.65m and 5.45m, respectively, in the three chances of long jump on the annual sports day. Find the average of the distances

Answer 1

Here is your answer.

Average = (5.25m+5.65m+5.45m)/3.

= 16.35m/3.

= 5.45m.

Hence, the average of the distances is 5.45m.

Hope it helps you.

Please mark my answer as the brainliest answer.

Answer 2

$\<b>Heya Mate$
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$\underline\bold{Step-by-step \: explanation}$
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Average= $\frac{Sum \: of \: observations}{No. \: of \: observations}$

=》 $\frac{5.25+5.65+5.45}{3}$
=》 $\frac{16.35}{3}$

=》 $\boxed{5.45}$

Hence, the average of his jumps will be 5.45 metres.
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$\sf\pink{Hope \: it \: helps \: you}$
$\sf\green{Please \: mark \: as \: the \: brainliest}$
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