Biology, asked by bhanukumar331, 10 months ago


Amino acid analysis of 1.0 mg of pure enzyme yielded 58.1 µg of leucine (MW = 131.2). What is the minimum MW of the enzyme based on leucine content?

Answers

Answered by venkatmahesh06
10

Answer:

Hii

Amino acid analysis of 1.0 mg of pure enzyme yielded 58.1 μg of leucine (MW = 131.2) What is the minimum MW of the enzyme based on leucine content? (1) 2000 (2) 2300

Answered by shradhdachaturvedi
1

Explanation:

1 mg --- 58.1 microgram of leucine

10-3--------. 58.1*10-6

W/m.w of enzyme = W/m.w of leucine

m.w of enzyme= m.w of leucine* m.w of enzyme/weight of leucine

=131.2* 10-3/58.1*10-6

= 131.2* 1000/58.1= 2258

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