Question

Amir has a right angular triangular tile measuring 3 units and 4 units.if he uses each of the three sides at least once while measuring , what will be the distance measured

Answer 1

$Dimensions \:of \:a \: right \: angular \\triangular \: tile : \\3 \:units \: and \:4 \:units$

$Let \: In \:\triangle ABC , \angle B = 90\degree \\AB = 4 \:units , BC = 3 \:units \\Third \:side (AC )= ?$

$\umderline {\pink { By \: Pythagoras\: Theorem:}}$

$AC^{2} = AB^{2} + BC^{2} \\= 4^{2} + 3^{2} \\= 16 + 9 \\= 25$

$\implies AC = \sqrt{25} \\= 5 \:units$

$Now, Distance \:measured \:at \:least \:once \\= Perimeter \:of \:the \: triangle \\= AB + BC + CA\}= (4 + 3 + 5 ) Units \\= 12 \:units$

Therefore.,

$\red {Distance \:measured \:at \:least \:once}\\\green {=12 \:units}$

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