Question

Amir was born on feb 29th of 2012 which was a wednesday. If he lives to be 101 years old, how many birthdays would he celebrate on a wednesday?

Answer 1

hey dude 29th feb is in leap year and for ur kind information he cant live for 101 years. which means 101×4 = 404.

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Answer 2

The correct answer is Amir would celebrate "four" birthdays if he lives to be a 101 years old who was born on feb 29th of 2012 which was a wednesday.

• The 29th of February occurs every four years, as is well known. Thus, 26 birthdays in total will be commemorated throughout the course of 101 years.

• Additionally, dates are shifted by one after every year, meaning that birthday dates are shifted by five days.
• This indicates that Wednesday will arrive on each of Amir's 7th birthdays.

• So the overall number of birthdays on Wednesday will be 4, according to a simple calculation.
• It will fall on the first, eighth, fifteenth, and twenty-second birthdays.

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