Amirah has 2 bottles of jelly beans, A and B. Bottle A has 400 jelly beans while Bottle B has 300 jelly beans. 75% of the jelly beans in Bottle A are red while the rest are yellow, 50% of the jelly beans in Bottle B are red while the rest are yellow. If Amirah moves some jelly beans from Bottle A to Bottle B such that 80% of the jelly beans in Bottle A are now red and 40% of those in Bottle B are yellow, find the number of jelly beans Amirah moves from Bottle A to Bottle B.
Answers
Answer:
Step-by-step explanation:
Amirah has 2 bottles of jelly beans.
A and B.
Bottle A has 400 jelly beans
Bottle B has 300 jelly beans
75% of the jelly beans in Bottle A are red while the rest are yellow = 400 × 75 /100 = 300 beans are red, 100 beans are yellow
50% of the jelly beans in Bottle B are red while the rest are yellow.
300 × 50 /100
= 150 are red beans in bottle B and 150 are yellow.
If 300 beans are 80% then 100 % will be =
300 /80 × 100
= 375
To make in Bottle A 80 % red beans so 25 yellow balls to be move to bottle B.
Now in bottle B , 150 + 25 = 175 yellow balls
Solution :-
- Bottle A :- 400 jelly beans => 75% are red and rest yellow .
so,
→ Red : yellow = 75 : 25 = 3 :1 => 300 and 100 .
and,
- Bottle B :- 300 jelly beans => 50% are red and rest yellow .
so,
→ Red : yellow = 50 : 50 = 1 :1 => 150 and 150 .
now, given that,
- 80% in Bottle A are now red.
- 40% in Bottle B are yellow .
A/q,
→ 80% = 300
→ 1 % = (300/80)
→ 100% = (15/4) * 100 = 15 * 25 = 375 .
therefore,
→ Total yellow beans removed from A = 400 - 375 = 25 beans . (Ans.)
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