Math, asked by ilapatel6979, 7 months ago

Amirt's age is 4 times that of broad's age. 10 years ago, Amir's age was 19 timas that of broad's age. The present age of amit and broad is ____ and ______​

Answers

Answered by prince820
0

Answer:

Amit's present age = 48 years

Broad's present age = 12 years

Step-by-step explanation:

Let Broad's present age be = x years

Therefore Amit's present age = 4x years

10 years ago:- Broad's age = x-10 years

Amit's age = 4x-10 years

Therefore, (4x-10) = 19(x-10) [As Amit's age before 10 years was 19 times as that of Broad)

4x-10 = 19x-190

4x-19x = - 190+10

-15x = -180

Therefore x = -180/-15 = 180/15 = 12

Therefore Broad's present age = x = 12 years

And Amit's present age = 4x = 4*12 = 48 years

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