Amit borrowed 20,000 at 12% per annum
compound interest. If he pays 40% of the sum
borrowed at the end of the first year and 40%
of the sum borrowed at the end of the second
year, find the amount of loan outstanding at the
beginning of the third year.( With full solution)
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Step-by-step explanation:
40/100 x 20,000 = 8000
P = 20,000
R = 12%
I = 20000 x 1 x 12 / 100
I = 2400
A at end of year 1 = 22400
Amit paid 8000 so pending money for second year will be 22400-8000 = 14,400
P = 14,400
R = 12%
I = 14400 x 1 x 12 / 100
I = 1728
A at the end of second year = 14400 + 1728 = 16128
Amit paid off 8000 again.
So remaining money is 16128-8000= 8120
(You can use the compound interest formula for both cases to get the same answer)
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