Math, asked by punit2343, 1 year ago

Amit borrowed Rs 4000 for 5 years. A paid Rs 5400 at the end of 5 years. How much will be have to pay on Rs 5600 in 3 years at the same rate as above?

Answers

Answered by isafsafiya
33

Answer:

he had to pay 6776

Step-by-step explanation:

solution------>

Given

  • P = 4000
  • N = 5
  • A = 5400

as per 1st condition......

we will find s.i

s.i = a - p \\  \\ s.i = 5400 - 4000 \\  \:  \:  \:  \:  \:  = 1400 \\  \\  \\ 1st \: we \: will \: find \:  \\ rate \: of \: intrest \: now \: as \: we \: know \\  \\ s.i =  \frac{p \times n \times r}{100}  \\  \\ 1400 =  \frac{4000 \times 5 \times x}{100}  \\  \\ 1400 = 40 \times 5 \times x \\  \\  x =  \frac{1400}{200}  \\  \\ x = 7 \\  \\

now for 2nd condition

we have

  • P= 5600
  • n =3
  • R =7%

s.i =  \frac{p \times n \times r}{100}  \\  \\   \:  \:  \:  \:  \:  =  \frac{5600 \times 7 \times 3}{100}  \\  \\  \:  \:  \:  \:  = 56 \times 21 \\  \\ s.i = 1176 \\  \\ a \:  = p + s.i \\  \\ a = 5600 + 1176 \\  \\ a = 6776

Answered by gadakhsanket
31

Dear Student,

● Answer -

Payment due after 3 years = 6776 Rs

● Explanation -

Suppose r be rate of interest.

Payment due = P (100 + r×t) / 100

5400 = 4000 (100 + r×5) / 100

100 + 5r = 5400 × 100 / 4000

5r + 100 = 135

5r = 135 - 100

5r = 35

r = 7 pcpa

After 3 years on Rs 5600 will be -

Payment due = P (100 + r×t) / 100

Payment due = 5600 (100 + 7×3) / 100

Payment due = 56 × (100 + 21)

Payment due = 56 × 121

Payment due = 6776 Rs

Hence, 6776 Rs will have to paid after 3 years.

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