Question

Amit bought 8 oranges for a rupee. to gain a profit of 60% how many for a rupee must he sell?

Answer 1

CP of 8 oranges = 1 Rs
Profit = 60 %

ATQ
Profit = 60/100 × 1
= 0.60 rs

SP = CP +PROFIT
= 1 + 0.60
= 1.60 RS

Answer 2

Answer:

He must sell 5 oranges for a rupee.

Step-by-step explanation:

Given,

He bought 8 oranges for a rupee,

Thus, the price of 8 oranges = 1 rupees,

⇒ The cost price of 1 orange = $\frac{1}{8}$ rupee,

Since, profit percentage = 60 %,

So, the profit in one orange = 60 % of the cost price

$=\frac{60}{100}\times \frac{1}{8}$

$=\frac{60}{800}$

$=\frac{3}{40}$

⇒ Selling price of one orange = Cost price + profit

$=\frac{1}{8}+\frac{3}{40}$

$=\frac{5+3}{40}$

$=\frac{8}{40}$

$=\frac{1}{5}\text{ rupee}$

⇒ 1 orange = 1/5 rupees,

⇒ 1 rupees = 5 oranges.

Hence, he must sell 5 oranges for a rupee.