Math, asked by sawkat890bhoumik, 1 month ago

Amit bought an article for 2310 and sold it at a loss of 25 %. With this money, he bought another article and soldit at a gain of 40 %. What was his overall gain or loss percent?
A) Loss 2.5%
B) Gain 8%
C) Loss 4%
D) Gain 5%

I hope you will give the right answer ​

Answers

Answered by nidsud2006
0

Answer:

D) Gain 5%

Step-by-step explanation:

First, calculate the amount he is left with after the first purchase and sale. that would be (100 - 25)/100 x 2310 (as this is a loss of 25% we can subtract that from 100). Therefore, he would be left with 1732.5. After this, he gained 40%. Hence, we can add 40 to 100, giving us 140% of 1732.5. Then we can do 140/100 x 1732.5 and the leftover amount would be 2425.5. Now we need to calculate the percentage profit of what he gained (it is profit because he started with 2310 and now has an extra of 115.5). Since we know the change in amount is 115.5, we can do 115.5/2310 (initial amount) x 100 (to get the percentage). He will get a profit of 5%.

Answered by Swarup1998
1

Step-by-step explanation:

Step 1.

Cost price of the first article = Rs. 2310

Loss = 25%

Then selling price of the first article

= Rs. 2310 (1 - 25/100)

= Rs. 2310 × 75/100

= Rs. 1732.50

Step 2.

Cost price of the second article = Rs. 1732.50

Profit = 40%

Then selling price of the second article

= Rs. 1732.50 (1 + 40/100)

= Rs. 1732.50 × 140/100

= Rs. 2425.50

Step 3.

Here cost price of the first price < selling price of the second article.

Then it was a profit for Amit.

Thus overall profit

= Rs. (2425.50 - 2310)

= Rs. 115.50

Therefore profit percentage

= profit / cost price of the first article × 100%

= 115.50/2310 × 100%

= 5%

Final answer: D) gain 5%

His overall gain percentage was 5%.

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