Question

Amit can complete a piece of work in 20 days and Sumit can complete the same in 24 days. They decide to complete the work by working on alternate days. If Sumit starts the work, how long will it take to complete the work?​

Answer 1

Step-by-step explanation:

hope it helps you buddy

Answer 2

Answer:

Ans: 8 days

Step-by-step explanation:

Amit can do a work in 20 days.

So in 1 day Amit can do =

$= \frac{1}{20} \: of \: work$

Sumit is 50% more efficient than Amit.

So Sumit can do =

$= \: \frac{3}{2} \: \: part \: of \: the \: work \: in \: 20 \: days$

. In 1 day sumit can do =

$= \frac{3}{(2 \times 20)} = \frac{3}{40} \: th \: of \: the \: work$

. When worked together both of them can do=

$\frac{1}{20} + \frac{3}{40} = \frac{(2 + 3)}{40} = \frac{5}{40} = \frac{1}{8}$

1/20+3/40=(2+3)/40=5/40=1/8 th part of work in 1 day. They will both finish the work in

1÷1/8 =8 days