Math, asked by utsav8731, 1 year ago

Amit is now 6 times old as his son. Four years after the sum of their ages will be 43 years, determine amit's present age?

Answers

Answered by astitvaawasthi
0

Answer:


Step-by-step explanation:

let amit's son age be x

therefore , let amit's age be 6x


Now 4 years later sum of their ages will be 43 years

which means (6x+4) + (x+4) = 43

6x+4+x+4 = 43

7x + 8 = 43

7x = 43-8

7x = 35

x = 35/7

x= 5

therefore son 's age is 5 years and amit's age is 6*x or 6*5 = 30


Answered by rathibhagwati3
0

Answer:


Step-by-step explanation:

Let, the present age of Amit's son be x years and that of Amit be 6x.

After four years;

(6x+4)+(x+4) = 43......given condition

=> 6x+4+x+4 = 43

=> 7x+8 = 43

=> 7x = 43-8

=> 7x = 35

=> x = 35/7

=> x = 5


Amit's present age = 6x = 6(5) = 30 years.

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