Question

amit is twice as old as his brother Manish . if the difference of their ages be 9 years find their present ages​

Answer 1

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let's take the age of Manish as =x

then, Amit will be =2x

they told difference between them is 13

if we write this in an equation we get,

2x-x=9

x=9

Manish is 13

Amit is 2*9.

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Amit is 18.

Answer 2

Solution:

let amit's age be x

and Manish's age be y

From first condition,

$x = 2y$

by second condition,

$x - y = 9$

Therefore by putting x=2y in second equation,

$(2y) - y = 9 \\ y = 9 \\ x = 2y = 2(9) = 18$

•°• Amit's age is 9 years and Manish's age is 18 years