Question

Amit is twice as old as his brother Sumit
. If the difference of their ages be 11 years, find
present ages.​

Answer 1

Answer:

11,22

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Answer 2

Answer:

♡Their present ages are 22 and 11 respectively.

Step-by-step explanation:

☆To find:

◇Present age of sumit and Amit

☆Given:

◇Difference of their age=11 years

◇Amit is twice as old as Sumit

☆Assuming:

◇Let the age of sumit be x

◇Therefore age of Amit =2x

☆Solution:

ATQ.

$2x - x = 11 \\ = > x = 11$

◇Therfore,

◇age of Amit=2x=2×11=22

☆Hence:

◇Age of Amit's is 22 years and Sumit's is 11 years.

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