Question

amit is twice as old as sumit. five years ago. his age is three times sumit's age. find their present ages​

Answer 1

Step-by-step explanation:

now just find the value of x you will get their present ages...

mark it as brainliest..

Answer 2

✬ Amit's age = 20 Years ✬

✬ Sumit's age = 10 Years ✬

Step-by-step explanation:

Given:

• Amit is twice as old as sumit.
• Five years ago Amit's age was three times of Sumit's age.

To Find:

• What is their present ages ?

Solution: Let Amit and Sumit age be x and y years respectively. Therefore,

➙ Amit's age = Twice of Sumit's age

➙ x = 2y....(1)

[ Now, 5 years ago their ages was ]

• Amit age = (x – 5) years
• Sumit age = (y – 5) years

A/q

• 5 years ago Amit was three times of Sumit age.

$\implies{\rm }$ (x – 5) = 3(y – 5)

$\implies{\rm }$ x – 5 = 3y – 15

$\implies{\rm }$ – 5 + 15 = 3y – x

$\implies{\rm }$ 10 = 3y – 2y

$\implies{\rm }$ 10 = y

So,

➯ Sumit present age is y = 10 years.

➯ Amit present age is x = 2y

=> 2(10) = 20 years.