Question

amit jogs form one end A to other end B of a straight 300 m road in 2 min 30 sec and then turns around and jogs 100 m back to point c in another 1 min. what are amit average speed and velocities in jogging (A)from A to B and (B) from A to C?

Answer 1

B from a to c is the answer

Answer 2

Average speed = total distance / total time

Average speed (A) = Distance from A to B/time
= 300 m / 2min 30sec
= 300m / 150sec
= 2m per second
Average velocity A is also same(300m/150sec) as displacement and the distance are same.

Average speed (B) = (Distance from A to B + Distance from B to C) / Total time
Total distance (A to C) = 300 + 100 m = 400m
Total time = 2min 30sec + 1min = 210sec
Therefore,
Average speed = 400m / 210 sec
= 40m per 21sec
Average velocity (B) = Displacement / time
Displacement (A to C) = +300 - 100 m (As Amit jogs back in same path in opposite direction)
Displacement (A to C) = 200 m
Time = 210 sec
Therefore,
Average velocity = 200m / 210 sec
= 20m / 221sec
I hope this will help you friend.