Question

Amit saves ₹400 in the first month ₹500 in the second month in the third month ₹600 and so on. How much will be his total savings in 21 months?​

Answer 1

Answer:

Step-by-step explanation:

his savings forms an A.P

therefore a=200

                d = 50

Sn=n/2 [2a+(n-1)d]

S17 = 17/2 [2 *200+(17-1)*50]

     = 17/2 [400 + 16*50]

     = 17/2 [400+800]

     =17/2 x 1200

     = 17 x 600

      =  Rs  10,200

do it like this the question is diff

Answer 2

₹10, 200

₹10, 200Step-by-step explanation:

₹10, 200Step-by-step explanation: saving forms an A. P

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d)

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d) s17=17/2(2×200+(17-1)×50)

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d) s17=17/2(2×200+(17-1)×50)17/2(400+800)

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d) s17=17/2(2×200+(17-1)×50)17/2(400+800)17/2×1200

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d) s17=17/2(2×200+(17-1)×50)17/2(400+800)17/2×120017×600

₹10, 200Step-by-step explanation: saving forms an A. P therefore a=200d=50sn=n/2(2a+(n-1) d) s17=17/2(2×200+(17-1)×50)17/2(400+800)17/2×120017×600₹10,200