Question

Amit saves certain amount every month in a specific way. In the first month he saves 200, in second he saves 250, in third month he saves 300 and so on. How much will be his total savings in 17 months​

Answer 1

10200  will be his total savings in 17 months​

Step-by-step explanation:

now look at the series formed

200 + 250 + 300 + ...........................  till 17 th term  

this is an A P series with common difference = 50

Sum of AP is given by:

S = $\frac{n}{2}$ ( 2a + d (n-1 ) )

d = 50

a = 200

n = 17

S= (2*200 + 16 * 50 ) * 17 / 2

 = (400+800 ) * 17 / 2

 = 600 * 17

 = 10200

Answer 2

Step-by-step explanation:

the AP becomes...

200,250,300,350..........17th term...

we hav to add all this 17 terms...

17th term = a+16d

= 200+16(50)

=200+800

=1000

so, 1st term is 200 and 17th term is 1000....

$s17 = \frac{n}{2} (1st \: term + last \: term) \\ \\ = \frac{17}{2} (200 + 1000) \\ \\ = \frac{17}{2} (1200) \\ \\ = 17 \times 600 \\ \\ = 10200$

Therefore....

he will save 10200 rupees at the end of 17th week....

mark it as brainliest...

mark it as brainliest...hope it helps....

@suhani678