Amit saves certain amount every month in a specific way. in the first month he saves rs 200, in the second month rs 250, in the third month rs 300 and so on. how much will be his total saving in 17 months?
Answers
Answered by
41
nice question
a=200
d=50
tn=?
n=17
therefore tn=[2a+(n-1)d]
t17=[2(200)+(17-1)50]
tn=[400+16(50)]
tn=[400+800]
tn=1000
therefore amit will save 1000Rs in 17months
..
hope it helps
a=200
d=50
tn=?
n=17
therefore tn=[2a+(n-1)d]
t17=[2(200)+(17-1)50]
tn=[400+16(50)]
tn=[400+800]
tn=1000
therefore amit will save 1000Rs in 17months
..
hope it helps
Answered by
6
Answer:
Step-by-step explanation:a=200
D=50
Formula: tn =a+(n-1)d
= 200+16×50
= 200+800
=1000
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