Amit Sharma:
At the beginning of a year ,the owner of a jewel shop raised the price of all the jewels in his shop by x% and lowered them by x%. The price of one jewel after this up and down cycle reduced by Rs.100.The owner carried out the same procedure after a month.After this second up-down cycle,the price of that jewel was Rs.2304.Find the original price of that jewel(in Rs.)
A. 3000
B.2700
C.2500
D.2000
Answers
Answered by
18
u can do it by 2 methods ...
Attachments:
panditamit4808:
great bro
Answered by
1
Answer:
2500
Step-by-step explanation:
let the price of jewel be y then after first raise
price = y*(100+x)/100
price has been decreased by that then new price
= y*(100+x)/100 * (100-x)/100
so y- [y*(100²-x²)/100}=100 (as given)
⇒100y-100y+x²y =100*100*100
⇒x²y=100*100*100
the process is repeated one more time then
we can find the answer by hit and trial method
answer is 2500
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