Amit sold a motorbike for rs 42x+20y+17.if the loss was rs 10 find the cos of motorbike.x=6 y=12
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2
Answer:
42 × 6 + 20 × 12 + 17 = 252 + 240 + 17 = 509
509 + loss ie 509 + 10 = 519 is the cp
Answered by
2
Step-by-step explanation:
motorbike selling price = 42x + 20 y + 17 rs
loss = 10 rs
given x= 6 ,y = 12
so 42x + 20y + 17
= 42 × 6 + 20 × 12 +17
= 252 + 240 + 17
= 309
selling price = 309
cost price = selling price + loss
= 309 + 10
= 319
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