Question

Amit, standing on a horizontal plane, find a bird flying at a distance of 200 m from him at an elevation of 30°. Deepak standing on the roof of a 50 m high building, find the angle of elevation of the same bird to be 45°. Amit and Deepak are on opposite sides of the bird. find the distance of the bird from Deepak. can we solve this question by taking distance of bird and amit on base side in triangle. ​

Answer 1

Answer:

Yeah, it will solved by properties of trigonometry.

Step-by-step explanation:

Answer 2

Solution:-

Let Amit is standing at point A, bird at point B, deepak at point D

height of the bird = BC, let E be a point on BC corresponding to point D at 50 m height

given,

AB = 200

∠A = 30°

∠D = 45°

In triangle ABC

Sin 30 = BC/AB

=> 1/2 = BC/200

=> BC = 100 m

=> BE = BC- EC = 100 - 50 = 50 m

In triangle,BED,

sin 45 = BE/BD

=> 1/√2 = 50/BD

=> BD = 50√2 = 70.7 m

Hence the distance of the bird from deepak is 70.7 m or approx 71

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@GauravSaxena01