Amit takes 20 days to complete a certain work. Amit started the work and Suraj joined him 4 days before the work was completed. Find out the number of days for which Amit worked alone if Suraj’s efficiency is 25% more than that of Amit’s
Answers
Given : Amit takes 20 days to complete a certain work.
Amit started the work and Suraj joined him 4 days before the work was completed.
Suraj’s efficiency is 25% more than that of Amit’s
To Find : the number of days for which Amit worked alone
Solution:
Amit 1 day work = A
Amit 20 days work = 20A
Total work = 20A
Let say after x day Suraj joined Amit
then Amit work for x + 4 days
and Suraj work for 4 day
Suraj’s efficiency is 25% more than that of Amit’s
=> Suraj 1 day work = A + (25/100)A = 5A/4
=> Suraj 4 day work = 4 * 5A/4 = 5A
Amit x + 4 days work =(x + 4)A
= xA + 4A
xA + 4A + 5A = 20A
=> xA = 11A
=> x = 11
Amit worked alone for 11 Days
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