Question

Amit walks 16 m south from his house and turns east to walk 63 m to reach his friends house. While returning, he walks diagonally from his friend's house to reach back to his house. What distance did he walk while returning?

Answer 1

Answer

your answer is 65 m

explanation

let the returning path be c

According  to Pythagorean Theorem of right angle triangle = $a^{2} + b^{2} = c$

A.T.Q.

         $\sqrt{16^{2} + 63^{2}$

         $\sqrt16 * 16 + 63 * 63$

          $\sqrt{256+3969$

           $\sqrt{4225$

            65 M

         

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