Question

Amit walks 16 m South from his house and turns East to walk 63 m to reach his friend's house . while returning he walked diagonally from his friend's house to reach back to his house what distance he walks while returning

Answer 1

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SUPPOSE AMIT IS AT THE POINT ⭕

HE WALKED 16 M IN SOUTH....

AND THEN 63 M TO EAST....AND REACHED ⭕

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MEANS HERE IS A RIGHT ANGLED TRIANGLE FORMED....

SO BY THE PYTHAGORAS THM.....

SO

16^2+63^2= the diagonal^2....

256+3969= the diagonal^2.....

4225= the diagonal^2

so diagonal =√4225

so DIAGONAL= 65 M

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SO THE DISTANCE BETWEEN HIS FRIEND'S HOUSE AND HIS HOUSE IS 65M

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

HOPE IT WILL HELP U MATE ☺❤☺

PLZ MARK AS BRAINLIEST ❤☺❤

⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕

Answer 2

Answer:

Distance covered in south=16m

Distance covered in east = 63m

Then he moved diagonally to return back home.

(If you will mame the figure you will see that it is a right angle triangle)

So using PGT

(H)^2=(P)^2 + (B)^2

(63)^2 = (P)^2 + (16)^2

P^2 = 3969 - 256

P^2 =3713

P= 60.93

plz mark as brainliest