Question

amit walks 16m south from his house and turns east to walk 63 m to reach his friend's house.while returning,he walks dioagonally from his friends house to reach back to his house.what distance did he walk while returning?

Answer 1

65m he walk during returning is answer

Answer 2

Answer:

Distance covered in south=16m

Distance covered in east = 63m

Then he moved diagonally to return back home.

(If you will mame the figure you will see that it is a right angle triangle)

So using PGT

(H)^2=(P)^2 + (B)^2

(63)^2 = (P)^2 + (16)^2

P^2 = 3969 - 256

P^2 =3713

P= 60.93

Step-by-step explanation:

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