Amit went to the market to buy some Diwali gifts for his family members.
He had some Rs 10 coins, some Rs 100 notes and some Rs 500 notes in
his wallet. The number of Rs 100 notes is three times the number of Rs
10 coins. Also, the number of Rs 500 notes is five more than the number
of Rs 100 notes. The total amount paid by Amit is Rs 11550, which is the
exact amount he had in his wallet. Find the number of Rs 10 coins he had
in his wallet.
Answers
Answer:
number of Rs 100 notes = 3 times of 10 coins
number of Rs 500 notes = 5 times of 100 notes
total amount paid by amit = 11550
total amount in wallet = 11550+3*10+5*100
11550+530
12080
remained money in wallet = 12080-11550 = 530.
Given: The number of Rs 100 notes is three times the number of Rs 10 coins. The number of Rs 500 notes is five more than the number of Rs 100 notes.
The total amount paid by Amit is Rs 11550.
To find: The number of Rs 10 coins he had in his wallet
Solution: Let the number of Rs 10 coins be x.
Therefore, the number of Rs 100 notes = 3x.
And the number of Rs 500 notes = 3x + 5.
Now according to the question,
x × 10 + 3x × 100 + (3x + 5)×500 = 11550
⇒ 10x + 300x + 1500x + 2500 = 11550
⇒ 1810x = 11550 - 2500
⇒ x = 9050/1810
⇒ x = 5
Hence, the number of Rs 10 coins he had in his wallet = 5.