Question

Amita invested some part of 35000 at 4% and the rest at 5% interest for 1 year. altogether her again was 1530. Find out the amount she had invested at the two different rates.

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Answer 1

Answer:

$\small\underline{\underline{\texttt{\red{ X = 22000}}}}$

$\small\underline{\underline{\texttt{\purple{ Y = 13000}}}}$

$\huge\underline\textsf{Explanation:-}$

Given x + y = 35000 — — — — —(1)

$\frac{4x}{1 00} + \frac{5y}{100} \: = 1530$

$\small\underline{\underline{\texttt{\purple{ Multiply \:each \:term \:by \:100}}}}$

We get ,

$\huge\rightarrow$ 153000 — — — —(2)

➡️ Multiply equations (1) and subtract from equation (2).

we get ,

$\large\mathtt{ 4x + 5y = 153000}$

$\large\mathtt{ 4x + 4y = 140000}$

$\large\underline\mathtt{ Y = 13000}$

$\rule{300}{3}$

$\large\mathtt{ Substitute\: Y \:value \:in \:equation \:(1)}$

we get,

$\small\underline{\underline{\texttt{\purple{ X + 13000=35000}}}}$

$\small\underline{\underline{\texttt{\purple{ X = 35000-13000}}}}$

X = 22,000

therefore,

$\rule{300}{2}$

$\small\underline{\underline{\texttt{\</strong><strong>blue</strong><strong>{ X = </strong><strong>22</strong><strong>,</strong><strong>000</strong><strong>}}}}$

$\small\underline{\underline{\texttt{\</strong><strong>green</strong><strong>{ </strong><strong>Y</strong><strong> = </strong><strong>13,</strong><strong>000}}}}$

$\rule{300}{2}$

✌ᴍᴀᴛʜsᴀʀʏᴀʙʜᴀᴛᴛA✌