Question

Amitbhai deposits certain amount from
60.000 at 3% and certain amount at 4%. He
receives 2200 as interest at the end of 1 year.
Find the amounts he deposited at different rate.​

Answer 1

Answer:

The amount deposited at 3% rate of interest is Rs 20,000

The amount deposited at 4 % rate of interest is Rs 40,000 .

Step-by-step explanation:

Given as :

Total principal money = Rs 60,000

Total interest received = I = 2200

The time period = t = 1 year

Let The amount deposited at 3 % rate of interest = Rs x

Let The amount deposited at 4 % rate of interest = Rs(60,000 - x)

According to question

From Simple Interest method

Simple Interest = $\dfrac{principal\times rate\times time}{100}$

Or, $I_1$ = $\dfrac{x\times 3\times 1}{100}$                ............A

Again

Simple Interest = $\dfrac{principal\times rate\times time}{100}$

Or, $I_2$ = $\dfrac{(60,000-x)\times 4\times 1}{100}$

∵ I = $I_1$  + $I_2$

So, I = $\dfrac{x\times 3\times 1}{100}$   +  $\dfrac{(60,000-x)\times 4\times 1}{100}$

Or, 100 I = 3 x + 240000 - 4 x

Or, 100 × 2200 = 240000 - x

Or, x = 240000 - 220000

i.e  x = Rs 20,000

∴ The amount deposited at 3% rate = x = Rs 20,000

And, The amount deposited at 4 % rate of interest = Rs(60,000 - x)

i.e The amount deposited at 4 % rate of interest = Rs(60,000 - Rs 20,000)

∴ The amount deposited at 4 % rate of interest = Rs 40,000

Hence, The amount deposited at 3% rate of interest is Rs 20,000

And  The amount deposited at 4 % rate of interest is Rs 40,000 . Answer

Answer 2

Step-by-step explanation:

Total principal money = Rs 60,000

Total interest received = I = 2200

The time period = t = 1 year

Let The amount deposited at 3 % rate of interest = Rs x

Let The amount deposited at 4 % rate of interest = Rs(60,000 - x)

According to question

From Simple Interest method

Simple Interest = \dfrac{principal\times rate\times time}{100}

100

principal×rate×time

Or, I_1I

1

= \dfrac{x\times 3\times 1}{100}

100

x×3×1

............A

Again

Simple Interest = \dfrac{principal\times rate\times time}{100}

100

principal×rate×time

Or, I_2I

2

= \dfrac{(60,000-x)\times 4\times 1}{100}

100

(60,000−x)×4×1

∵ I = I_1I

1

+ I_2I

2

So, I = \dfrac{x\times 3\times 1}{100}

100

x×3×1

+ \dfrac{(60,000-x)\times 4\times 1}{100}

100

(60,000−x)×4×1

Or, 100 I = 3 x + 240000 - 4 x

Or, 100 × 2200 = 240000 - x

Or, x = 240000 - 220000

i.e x = Rs 20,000

∴ The amount deposited at 3% rate = x = Rs 20,000

And, The amount deposited at 4 % rate of interest = Rs(60,000 - x)

i.e The amount deposited at 4 % rate of interest = Rs(60,000 - Rs 20,000)

∴ The amount deposited at 4 % rate of interest = Rs 40,000

Hence, The amount deposited at 3% rate of interest is Rs 20,000

And The amount deposited at 4 % rate of interest is Rs 40,000 . Answer