Amixture was found to contain 1.50 g NH4Cl, 0.80 g NaCl, and 1.20 g SiO2. What is the percentage of sand in this mixture?
Answers
Answered by
0
percentage of send=percentage of si02
=1.20/1.50+0.80+1.20×100
=34.28persent
I hope it is helpful to you
Similar questions