Question

Ammeter reads 2.0 a and the voltmeter reads 12v.
how much energy is transferred in the resistor in 10 seconds.

Answer 1

Answer:

240J

Explanation:

given ,

ammeter reading current is 2 A

voltmeter reading 12 v

ohm's law V=I.R

R is V/I

R is 12/2 is 6 ohms

energy ,is i^2 .R.t

time is 10sec

energy is (2)^2.6.10

=4.6.10

240 J