Chemistry, asked by ammaranadeem, 9 months ago

Ammonia gas can be produced by heating together the solid NH4Cl and calcium hydroxide. If a mixture containing 100g of each of these solids is heated, how many grams of NH3 are produced? also find the volume of NH3 gas at STP. 2NH4Cl + Ca(OH)^2___》2NH3 + CaCl2 + 2H2O

Answers

Answered by aryankadam2002p3zgef
0

Answer:Ca(OH)2 +2 NH4Cl -> CaCl2 + 2 NH3 + 2H2O.

Thus 1 mole of Ca(OH)2 requires 2 moles of NH4Cl.

number of moles of in 100 g of each of reactants is

for Ca(OH)2 100 g / 74g mol^-1 = 1.35 moles

for NH4Cl. 100 g÷ 53.5 g mol^-1= 1.87 moles

In this case, NH4Cl is a limiting reagent

1.87 moles of it will react with 1.35/2= 0.675 moles of Ca(OH)2 producing 1.35 moles of NH3 i.e. 34 g × 1.35 =45.9 g of it.

Since 1 mole of any gas occupies 22.4 L

1.35 × 22.4 L corresponds to 30.24 L .

Explanation:

Answered by bestwriters
2

31.62 grams of NH₃ are produced.

The volume of NH₃ gas at STP is 41.664 L.

Explanation:

2NH₄Cl + Ca(OH)₂  →  2NH₃ + CaCl₂ + 2H₂O

From the above reaction, 2 moles of ammonium chloride and 1 mole of calcium hydroxide produces 2 moles of ammonia.

The number of moles of ammonium chloride is:

⇒ 100/53.5 = 1.86 moles

The number of moles of calcium hydroxide is:

⇒ 100/74 = 1.35 moles

1 mole of calcium hydroxide reacts with 2 moles of ammonium chloride:

From reaction, 1.35 moles of calcium hydroxide requires 1.35 × 2 = 2.7 moles of ammonium chloride which is not accessible.

Hence, Calcium hydroxide is not limiting reagent.

2 moles of ammonium chloride reacts with 1 mole of calcium hydroxide :

So 1.86 of ammonium chloride requires 1.86/2 = 0.93 moles of calcium hydroxide which is available.

Hence, ammonium chloride  is limiting reagent.

Unreacted moles of calcium hydroxide = 1.35 - 0.93 = 0.42 moles

Now, 2 moles of ammonia are formed from 2 moles of ammonium chloride.

Therefore 1.86 moles would be formed from 1.86 moles of ammonium chloride.

Weight of ammonia produced = 1.86 × 17 = 31.62 grams

1 mole of ammonia measures 22.4 L at STP

1.86 mole would measure 1.86 × 22.4 = 41.664 L at STP.

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