Ammonia gas diffuses twice as fast as do
gas X. The gas 'X'is
2) C4H10 3) C3H, 4) Cl2
1) SO2
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Answer:
the answer is SO₂
the rate of diffusion depends inversely on the root of molar mass.
so the r₂/r₁=√m₁/m₂
so 2/1= √x/√17
so x =68 and 68 is S0
₂
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