Question

Ammonia gas occupies a volume of 450mL at a pressure of 720 atm. What volume will it occupy at standard pressure stp?
answer is 324,000 ml



I need process​

Answer 1

Answer:

According to boyle's law, P is inversely proportional to V

Answer 2

The volume Ammonia gas will occupy at standard pressure STP = 324000 ml

Given :

Ammonia gas occupies a volume of 450mL at a pressure of 720 atm.

To find :

The volume Ammonia gas will occupy at standard pressure

Solution :

Step 1 of 2 :

Write down the given data

By the given condition

P₁ = Initial pressure = 720 atm

V₁ = Initial volume = 450 ml

P₂ = Final pressure = Standard pressure= 1 atm

V₂ = Final volume = ?

Step 2 of 2 :

Calculate volume Ammonia gas will occupy at standard pressure

By Boyle's law we have

$\displaystyle \sf P_1V_1 =P_2V_2$

$\displaystyle \sf{ \implies }720 \times 450 =1 \times V_2$

$\displaystyle \sf{ \implies }720 \times 450 = V_2$

$\displaystyle \sf{ \implies } V_2 = 720 \times 450$

$\displaystyle \sf{ \implies } V_2 = 324000$

Hence volume Ammonia gas will occupy at standard pressure STP = 324000 ml

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