Question

Ammonia is formed from the reactants nitrogen and hydrogen in presence of a catalyst under suitable conditions . assuming all volumes are measured in litres at s.t.p .Calculate the volume of ammonia formed if only 10%conversion has taken place

Answer 1

N2 + 3 H2    ==>   2 N H3
 x       3 * x               2 * x

   x liters of Nitrogen and 3 x liters of Hydrogen produce 2 x liters of Ammonia.
Initially V liters of N2,  and  3*V liters of H2 are present.  Only 10% conversion took place.

So  0.90 V liters of N2 and 2.70 V liters of H2 are remaining. And, 0.20 V liters of Ammonia is produced.

Produced Ammonia has a volume equal to 20% of initial volume of Nitrogen.

Answer 2

reaction for the formation of ammonia:

N2 + 3H2 → 2NH3

It can be seen that 1 mole of N2 and 3 moles of H2 together 4 moles of reactants produce 2 moles of ammonia

If only 10% conversion takes place,

0.4 moles of reactants will produce 0.2 moles of ammonia

At STP, in term of molar volume:

0.4 x 22.4 = 8.96 L of reactants will produce 0.2 x 22.4 = 4.48 L of ammonia