Question

Ammonia is manufactured based on the following chemical equation :
N2(g) + 3H2(g) →2NH3(g).
Find the volume of NH3(g) produced when 0.01 moles of N2(g) is reacting.

Answer 1

Refer the attachment

I hope this helps ( ╹▽╹ )

Answer 2

Answer- The above question is from the chapter 'Some Basic Concepts of Chemistry'.

Question: Ammonia is manufactured based on the following chemical equation:

N₂(g) + 3H₂(g) →2NH₃(g).

Find the volume of NH3(g) produced when 0.01 moles of N2(g) is reacting.

Answer: N₂(g) + 3H₂(g) →2NH₃(g)

According to Stoichiometry, we see that,

1 mole of N₂ reacts with 3 moles of H₂ to form 2 moles of NH₃.

                                  N₂                     2NH₃  

                                   1             →            2

                                 0.01          →          2 × 0.01 = 0.02

So, we will have 0.02 moles of NH₃.

We know that any gas at STP has volume = 22.4 L

⇒ 1 mole of NH₃ has volume = 22.4 L

So, 0.02 moles of NH₃ has volume = 22.4 × 0.02 = 0.448 L = 448 ml

∴ Required volume of NH₃ = 0.448 L or 448 ml.