Ammonia produced by 0.75 g substance during nitrogen estimation in an organic compound by Kjeldahl’s method requires 15 cm3 of 0.5 N H2SO4. The percentage of nitrogen in the compound is??
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Given:
m = 0.5 gm
N = 0.5 N
Volume of H2SO4 consumed, (V-V₁/2) = 15 cm³ = 15 ml
To Find:
The percentage of nitrogen in the compound.
Calculation:
- We know that for H2SO4, n = 2
⇒ M = N / n
⇒ M = 0.5 / 2
⇒ M = 0.25 M
- For Kjelhdal's method:
% of N = 1.4 × M × 2 × (V-V₁/2) / m
⇒ % of N = 1.4 × 0.25 × 2 × 15 / 0.75
⇒ % of N = 14 %
- So the percentage of nitrogen in the compound is 14 %
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