Ammonia reacts with oxygen to form nitrogen dioxide and steam, as follows: 4 NH3(g) + 7 O2(g) →4 NO2(g) + 6H2O(g) Given the following standard enthalpies of format kJ.mol), calculate the enthalpy of reaction.
NH3(g) = -45.90
NO2 (g) = +33.1
H2O(g) = -241.83
Answers
Answered by
1
Answer:
bhai kya meri ek help kroge
Similar questions