Question

Ammonia under a pressure of 15 atm at 27°C is heated to 347°C in a closed vessel in the presence of a catalyst. Under the conditions, NH3 is partially decomposed according to the equation. 2NH N 3H 3 2 2    . The vessel is such that the volume remains effectively constant whereas pressure increases to 50 atm. Calculate the percentage of NH3 actually decomposed 1) 65% 2) 61.3% 3) 62.5% 4) 64%

Answer 1

Answer:

Explanation:

Case 1

P proportional to T

15 /P = 300/620

p = 31

This pressure containing ammonia is then dissociated

2NH3 -----> 3H2   + N2

31-x             3x/2      x/2

To form 50 atm total

50 = 31 +x

x =  19

Percentage f ammonia dissociated

    =  19/31 x 100  = 61.3

Answer 2

Explanation:

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