Chemistry, asked by guptauday49, 11 months ago

Ammonium carbamate dissociates as follows:
NH2COONH4 (S) 2NH3,(g)+CO2,(g)
The value of Kp, for this reaction is found to be equal to
2.92 * 10^-5 atm^3. If one mole of ammonium carbamate is
heated in a sealed container, the total pressur develped
in the container is
(A) 0.0194 atm
(B) 0.0388 atm
(C) 0.0582 atm
(D) 0.0667 atm​

Answers

Answered by saurabh3j
0

If the value of Kp is equal to 2.92atm then the pressure developed will be 0.0582

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