Question

Ammonium carbonate when heated to 200C gives NH3 and CO2 vapour with density 13. Find degree of dissociation?

Answer 1

As we know 
K = Cα²/ 1-α

and 1-α =1 

Kα = Cα²
α= √Kα/ C

α= 1/√c

by considering the concentration at 1M
degree of dissociation = α= 1

Answer 2

Hey dear,

● Answer -
Degree of dissociation is 1.

● Explanation -
Let α be degree of dissociation and m be initial conc.

On heating, (NH4)2CO3 decomposes to NH3, H2O & CO2
Reaction : (NH4)2CO3 --> 2NH3 + CO2 + H2O
Initially : m 0 0 0
Equilibrium : m(1-α) 2αm αm αm

Vant Hoff factor is calculated as -
i = total conc. / initial conc.
i = [m(1-α) + 2αm + αm + αm] / m
i = 1 + 3α

But also,
i = sum of no. of ions in the product
1 + 3α = 2 + 1 + 1
α = 1

Hello, degree of dissociation is 1.


Hope this helps you..