Question

Ammonium hydrogen sulphide dissociates as: NH_HSs) = NH3(g) + H2SO). Solid NH HS is heated to a temperature TK in a closed vessel containing NH3 at 0.1 atm. If the equilibrium pressure is 0.5 atm. The equilibrium constant K, for the dissociation reaction is:​

Answer 1

Answer:

Explanation:

total pressure of ammonia + hydrogen sulfide = 1atm

Therefore,  pressure of ammonia=pressure of hydrogen sulphide = 1/2

=0.5atm

The values of Kp can be calculated as,

Kp = ( NH3 atm ) ( H2S atm )

   

    Kp = $0.25 atm^{2}$

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