Ammonium hydrogen sulphide is contained in a closed vessel at 313 K when total pressure at equilibrium
is found to be 0.8 atm. The value of K, for the reaction, NH HS() NH.(g) + H S(g) is
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Ammonium hydrogen sulphide is contained in a closed vessel at 313K313K when total pressure at equilibrium is found to be 0.80.8 atm. The value of {K}_{p}K
p
for the reaction,
{ NH }_{ 4 }HS(s)\rightleftharpoons { NH }_{ 3 }(g)+{ H }_{ 2 }S(g)NH
4
HS(s)⇌NH
3
(g)+H
2
S(g) is:
Asked on November 22, 2019 by
avatar
Niviya Sundaravathanam
1 answer
Ammonium hydrogen sulphide is contained in a closed vessel at 313K313K when total pressure at equilibrium is found to be 0.80.8 atm.
{ NH }_{ 4 }HS(s)\rightleftharpoons { NH }_{ 3 }(g)+{ H }_{ 2 }S(g)\quadNH
4
HS(s)⇌NH
3
(g)+H
2
S(g)
P_{NH_3} = P_{H_2S} = PP
NH
3
=P
H
2
S
=P
Total pressure P_{NH_3} + P_{H_2S} = P+P=2PP
NH
3
+P
H
2
S
=P+P=2P
But total pressure is 0.8 atm.
2P=0.82P=0.8
P=0.4P=0.4 atm
P_{NH_3} = P_{H_2S} = P =0.4P
NH
3
=P
H
2
S
=P=0.4 atm
The value of the equilibrium constant for the reaction, is {K}_{p} = P_{NH_3} \times P_{H_2S}K
p
= P
NH
3
×P
H
2
S
{K}_{p} = 0.4 \times 0.4K
p
= 0.4×0.4
{K}_{p} = 0.16K
p
= 0.16