Question

Ammonium hydroxide solution is added to solution 'A', pale blue precipitate is formed which is soluble in excess of ammonium hydroxide forms inky blue solution. Name the metal ion present in solution 'A'

Answer 1

Answer:

CuSO4+2NH4OH→(NH4)2SO4+Cu(OH)2(pale−blue)

The cation present in solution B is Copper (Cu+2).

The color of solution B is Blue.

The pale blue precipitate of copper hydroxide dissolves in excess of ammonium hydroxide forming tetraamine copper [II] sulphate, an azure blue(deep blue) soluble complex salt.

Cu(OH)2+(NH4)2SO4+2NH4OH→[Cu(NH3)4]SO4+4H2O

Explanation:

Please mark me as a brainlist