Question

Ammonua gas is passed into water yielding a solution of density 0.93 g/cm^3 and containing 18.6% nh3 by weight.the mass of nh3 per cc of the solution is

Answer 1

Molarity = %w/w × 10× d / GMM

              = 18.6×10×0.93 / 17
             
              10.175 mole/litre 

now,   Moles = w  / molar mass
          10.175  = w / 17
               w = 10.175×17 
                  = 172.975 g


∵ 1000 ml soln contains mass of NH3 = 172.975 g

∴ 1 ml soln will contain mass of NH3 = 172.975/1000 

                                                          0.17 g